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A boy sits 1.0 meters from the center of a merry go round, he spins at 20 rpms , what's the velocity

Sagot :

We know , [tex]1 \ rpm = \dfrac{2\pi}{60}\ rad/s[/tex]

So, [tex]20 \rpm = 20\times \dfrac{2\pi}{60} = \dfrac{2\pi}{3}\ rad/s\\[/tex]

It is also given that, boy sits 1.0 meters away from the center of the merry go round.

Solution :

We know, velocity of at distance r from center in a circular body is given by :

[tex]velocity = \omega \times r\\\\velocity = \dfrac{2\pi}{3}\times 1 \\\\velocity = \dfrac{2\pi}{3}\\\\velocity = 2.09\ m/s[/tex]

Therefore, the velocity of boy is 2.09 m/s.