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Sagot :
Divisibility rule of 2-last digit divisibility
Divisibility rule of 3-sum of digit divisibility
Divisibility rule of 4-last 2 digits divisibility
Divisibility rule of 5-last digit 0 or 5
Divisibility rule of 6-divisible by both 2 and 3
Divisibility rule of 9-sum of digits divisibility
Divisibility rule of 10-last digit 0
Now we can see that last digit 6 is divisible by 2
2+6+1+6=15 is divisible by 3
16 is divisible by 4
6 is not 0,5 so 2616 is not divisible by 5
2616 divisible by both 2 and 3 so its divisible by 6
2+6+1+6=15 is not divisible by 9
6 is not 0 so 2616 is not divisible by 10
Hope it helped!
Answer:
It's divisible by 2, 3, 4, and 6 (not divisible by 5, 9 or 10)
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