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Determine whether 2,616 is divisible by 2, 3, 4, 5, 6, 9, or 10?​

Sagot :

Divisibility rule of 2-last digit divisibility

Divisibility rule of 3-sum of digit divisibility

Divisibility rule of 4-last 2 digits divisibility

Divisibility rule of 5-last digit 0 or 5

Divisibility rule of 6-divisible by both 2 and 3

Divisibility rule of 9-sum of digits divisibility

Divisibility rule of 10-last digit 0

Now we can see that last digit 6 is divisible by 2

2+6+1+6=15 is divisible by 3

16 is divisible by 4

6 is not 0,5 so 2616 is not divisible by 5

2616 divisible by both 2 and 3 so its divisible by 6

2+6+1+6=15 is not divisible by 9

6 is not 0 so 2616 is not divisible by 10

Hope it helped!

Answer:

It's divisible by 2, 3, 4, and 6 (not divisible by 5, 9 or 10)