Answered

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R varies directly as p^2 and inversely as t. When p= 8 and t = 16, R = 8. What is the value of R when p =4 and t = 32?

Sagot :

ayfat23

Answer:

R=1

Step-by-step explanation:

R ∝ p^2 /t

If we introduce proportionality constant K, we have

R = Kp^2 /t .......eqn(1)

When p= 8 and t = 16, R = 8

Substitute values of p,t, R into eqn(1)

8= (K × 8^2 )/ 16

8= 64K/16

64K= 16×8

64K= 128

K=2

What is the value of R when p =4 and t = 32

R = Kp^2 /t

R=( 2 × 4^2) /32

= 32/32

R=1

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