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joe is 4 years older than 2 times sam's age. the sum of their age is 25. find their ages

Sagot :

Answer:

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Step-by-step explanation:

When solving algebraic word problems, we usually assign the variable to the standard of comparison.  In this case, the standard of comparison is the age of Tom, so  

Let x = Tom's age.  Then

"4 less than twice the age of Tom" translates to 2x - 4.

The sum of their ages is 41, so

x + 2x - 4 = 41

Simplifying,

3x - 4 = 41

3x = 45

x = 15

Therefore, Tom is 15, Joe is 2(15) - 4 = 26