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find factors of g(x)=2x^3+3x^2-23x-12 when (2x+1) is a factor

Sagot :

Answer:

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

 (((2 • (x3)) -  3x2) -  23x) +  12

STEP  

2

:

Equation at the end of step

2

:

 ((2x3 -  3x2) -  23x) +  12

STEP

3

:

Checking for a perfect cube

3.1    2x3-3x2-23x+12  is not a perfect cube

Trying to factor by pulling out :

3.2      Factoring:  2x3-3x2-23x+12  

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -23x+12  

Group 2:  2x3-3x2  

Pull out from each group separately :

Group 1:   (-23x+12) • (1) = (23x-12) • (-1)

Group 2:   (2x-3) • (x2)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

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