Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Can someone help me with number 12 ?


Can Someone Help Me With Number 12 class=

Sagot :

Answer:

3x= 2y +6

and when we put y = 0

then 3x = 6

x = 6/3

x =2

SECOND one , when we put x = 0

0= 2y +6

-6 = 2y

-6/2= y

-3 = y

Steps:
3x - 2(0) = 6
3x = 6
X = 2

Plug 2 into the equation

3(2) - 2y = 6
6 - 2y = 6
6 = 6 + 2y
0 = y

If this is wrong try doing it the opposite way which is:

3(0) - 2y = 6
-2y = 6
Y = -3

3x - 2(-3) = 6
3x + 6 = 6
3x = 0
X = 0