raquanbazemore1
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Factor the quadratic expression x2-19x+88 (x+__)(x+__) ^ Where the answer would go​

Sagot :

Answer:

(x+8)(x+11)

Step-by-step explanation:

When you factor a quadratic by the form:

[tex]x^{2} + bx + c[/tex]

you are looking for two numbers, 'q' and 'r', which ADD to 'b' and MULTIPLY to 'c'.

In this case, some example numbers that multiply to 88 are:

±1, ±2, ±4, ±8, ±11, ±44, ±88.

Since they must add to 19, then you can figure out through some trial and error that the numbers are 8 and 11.

8*11 = 88

8+11 = 19

So, the answer is (x+8)(x+11)

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