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Pls I Need Help Answering This class=

Sagot :

Answer:

477 moles of KNO₃

Explanation:

From the question above.

If 1 mole of anything = 6.02×10²³ molecules,

Thenn, X mole of KNO₃ will be 2.87×10²⁶ molecules of KNO₃

i.e,

1 mole of KNO₃ ⇒ 6.02×10²³ molecules of KNO₃

X mole of KNO₃ ⇒ 2.87×10²⁶ molecules of KNO₃

Solving for X

X = (1 mole of KNO₃× 2.87×10²⁶ molecules of KNO₃)/6.02×10²³ molecules of KNO₃

X = 476.7 moles of KNO₃. ≈ 477 moles of KNO₃

Hence the right Option is 477.