Given:
The figure of a right angle triangle.
To find:
The value of x and measures of all angles of the triangle.
Solution:
According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees.
Using angle sum property, we get
[tex](x+60)^\circ+(x+50)^\circ+90^\circ=180^\circ[/tex]
[tex](2x+200)^\circ=180^\circ[/tex]
[tex](2x)^\circ=180^\circ-200^\circ[/tex]
[tex](2x)^\circ=-20^\circ[/tex]
It can be written as
[tex](2x)=-20[/tex]
Divide both sides by 2.
[tex]x=-10[/tex]
The value of x is -10.
Now,
[tex]m\angle A=x+50[/tex]
[tex]m\angle A=-10+50[/tex]
[tex]m\angle A=40[/tex]
And,
[tex]m\angle B=x+60[/tex]
[tex]m\angle B=-10+60[/tex]
[tex]m\angle B=50[/tex]
Therefore, the value of x is -10, measure of angle A is 40 degrees and measure of angle B is 50 degrees.
