Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

PLEASE HELP I NEED THIS ASAP

PLEASE HELP I NEED THIS ASAP class=

Sagot :

Given:

The exponential function is

[tex]y=2200(1.074)^x[/tex]

To find:

The percentage rate of increase or decrease.

Solution:

The general form of an exponential function is

[tex]y=a(1+r)^x[/tex]         ...(i)

Where, a is the initial value, r<0 is the rate of decrease, r>0 rate of increase, x is time period.

We have,

[tex]y=2200(1.074)^x[/tex]

It can be written as

[tex]y=2200(1+0.074)^x[/tex]           ...(ii)

On comparing (i) and (ii), we get

[tex]r=0.074[/tex]

r>0, so the it is the rate of increase. Multiply it by 100 to get the percentage rate of increase.

[tex]r=0.074\times 100\%[/tex]

[tex]r=7.4\%[/tex]

Therefore, the percentage rate of increase is 7.4%.