Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

rearrange U=1/2KX2 make x the subject

Sagot :

= 1/2kx2

U = potential energy of a spring at a certain position

k = the spring constant, specific to the spring, with units N/m.

x = distance the spring is stretched or compressed away from equilibrium

Potential Energy: Elastic Formula Questions:

1) A spring, which has a spring constant k = 7.50 N/m, has been stretched 0.40 m from its equilibrium position. What is the potential energy now stored in the spring?

Answer: The spring has been stretched x = 0.40 m from equilibrium. The potential energy can be found using the formula:

U = 1/2kx2

U = 1/2(7.50 N/m)(0.40 m)2

U = 0.60 N∙m

U = 0.60 J

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.