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Sagot :
9514 1404 393
Answer:
D. The ball was thrown from an initial height of 3 feet.
Step-by-step explanation:
The generic form of the equation for (vertical) ballistic motion is ...
[tex]h(t)=-\dfrac{1}{2}gt^2+v_0t+h_0[/tex]
where g is the acceleration due to gravity, usually approximated as 32 ft/s², v₀ is the initial upward velocity, and h₀ is the initial height.
The given equation matches the situation where the object was launched vertically at the rate of 40 ft/s from a height of 3 ft.
The 3 represents an initial height of 3 feet.
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