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Find the area of triangle ABC.
Give your answer correct to 1 decimal place.

Find The Area Of Triangle ABC Give Your Answer Correct To 1 Decimal Place class=

Sagot :

Answer:

Soln:

Given

sides(s)=10,8,9

Semi perimeter(p)=a+b+c/2

= 10+9+8/2

=13.5

Area of triangle(a)=

[tex] \sqrt{s(s - a)(s - b)(s - c)} [/tex]

[tex] = \sqrt{13. 5(13.5 - 10)(13.5 - 9)(13.8 - 8)} [/tex]

=34.19

=35cm(ANS)

shubhamchouhanvrVT

The area of the given triangle will be equal to 35cm.

What is an area?

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the triangle in a two-dimensional plane is called the area of the triangle.

Given that:-

sides(s)=10,8,9

Semi perimeter(p)   =   a  +  b  +  c  /  2

=   10  +   9  +  8   /   2

=  13.5

The area of a triangle(a) will be calculated as:-

[tex]A =\sqrt {s(s-a)(s-b)(s-c)[/tex]

[tex]A= \sqrt{13.5[(13.5-9)(13.5-8)(13.5-10)[/tex]

A  =  34.19

Therefore the area of the given triangle will be equal to 35cm.

To know more about an area follow

https://brainly.com/question/25292087

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