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solve the quadratic equation 2x^2-5x+1=x+4​

Sagot :

altavistard

Answer:

Step-by-step explanation:

Combine like terms in 2x^2-5x+1=x+4:  2x^2 -6x - 3 = 0

The coefficients of this quadratic are {2, -6, -3}.  Apply the quadratic formula.  Start by finding the discriminant, b^2 - 4ac:

b^2 - 4ac = (-6)^2 - 4(2)(-3) = 36 + 24 = 60

Because the discriminant (60) is positive, we know that this quadratic has two real, unequal roots:

      -(-6) ± √60          6 ± (√4)(√15)

x = -------------------- = ----------------------

             2(2)                         4

or:

      6 ± 2√15            3 ± √15

x = -----------------  =  ----------------

              4                       2

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