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Please help #12.....

Please Help 12 class=

Sagot :

ac04yt

Answer:

DE = 7

Step-by-step explanation:

I don't have a great way of explaining so stay with me.

Both of these triangle are supposedly congruent since you can find DE.

You have to rotate CDE to line up correctly with FGH.

C and F are the same. D and G are the same. E and H are the same.

So after you match them up you can see the CD and FG are are on the same line.

If you do 13[tex]\frac{1}{3}[/tex] divided by 8 (or FG divided by CD) you get 1[tex]\frac{2}{3}[/tex]

After you match them up you can also see that CE and FH are on the same line.

If you do 10 divided by 6 (or FH divided by CE) you also get 1[tex]\frac{2}{3}[/tex]

With this pattern you should be able to figure  out that if you divide 11[tex]\frac{2}{3}[/tex] by 1[tex]\frac{2}{3}[/tex] that you will find DE.

DE is 7