Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

2 cot^2t sin t - cot^2t = 0

Sagot :

LammettHash

2 cot²(t ) sin(t ) - cot²(t ) = 0

cot²(t ) (2 sin(t ) - 1) = 0

cot²(t ) = 0   or   2 sin(t ) - 1 = 0

cot(t ) = 0   or   sin(t ) = 1/2

cos(t ) / sin(t ) = 0   or   sin(t ) = 1/2

cos(t ) = 0   or   sin(t ) = 1/2

[t = cos⁻¹(0) + 2nπ   or   t = cos⁻¹(0) - π + 2nπ]

  or   [t = sin⁻¹(1/2) + 2nπ   or   t = π - sin⁻¹(1/2) + 2nπ]

(where n is any integer)

t = π/2 + 2nπ   or   t = -π/2 + 2nπ   or   t = π/6 + 2nπ   or   t = 5π/6 + 2nπ

Note that the first two families of solutions overlap and can be condensed, so that

t = π/2 + nπ   or   t = π/6 + 2nπ   or   t = 5π/6 + 2nπ

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.