Answered

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2 cot^2t sin t - cot^2t = 0

Sagot :

LammettHash

2 cot²(t ) sin(t ) - cot²(t ) = 0

cot²(t ) (2 sin(t ) - 1) = 0

cot²(t ) = 0   or   2 sin(t ) - 1 = 0

cot(t ) = 0   or   sin(t ) = 1/2

cos(t ) / sin(t ) = 0   or   sin(t ) = 1/2

cos(t ) = 0   or   sin(t ) = 1/2

[t = cos⁻¹(0) + 2nπ   or   t = cos⁻¹(0) - π + 2nπ]

  or   [t = sin⁻¹(1/2) + 2nπ   or   t = π - sin⁻¹(1/2) + 2nπ]

(where n is any integer)

t = π/2 + 2nπ   or   t = -π/2 + 2nπ   or   t = π/6 + 2nπ   or   t = 5π/6 + 2nπ

Note that the first two families of solutions overlap and can be condensed, so that

t = π/2 + nπ   or   t = π/6 + 2nπ   or   t = 5π/6 + 2nπ

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