Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Of a total of 6,000.00, part was invested at a simple interest rate of 8% and part at 7% if the total interest income for one year was $46.00, how many was invested at 7%

Sagot :

Answer: Ok so first 0.05(6000 - x) + 0.07x = 372

300 - 0.05x + 0.07x = 372

300 + 0.02x = 372

0.02x = 72

x = 3600

He invested $3600 at 7% and $2400 at 5%.

Hope this helps have a bless day❤️

Step-by-step explanation:

irspow

Answer:

Step-by-step explanation:

I think you had a typo where interest should be 460 not 46 because even if the whole 6000 were invested at 7% he would have earned $420 in interest. Also if total investment was switched from 6000 to 600 the 46 in interest would work.

.07x+.08(6000-x)=460

.07x-.08x+480=460

-.01x+480=460

-.01x=-20

x=$2000

which is easy enough to check

2000(.07)+4000(.08)=$460

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.