Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Of a total of 6,000.00, part was invested at a simple interest rate of 8% and part at 7% if the total interest income for one year was $46.00, how many was invested at 7%

Sagot :

Answer: Ok so first 0.05(6000 - x) + 0.07x = 372

300 - 0.05x + 0.07x = 372

300 + 0.02x = 372

0.02x = 72

x = 3600

He invested $3600 at 7% and $2400 at 5%.

Hope this helps have a bless day❤️

Step-by-step explanation:

irspow

Answer:

Step-by-step explanation:

I think you had a typo where interest should be 460 not 46 because even if the whole 6000 were invested at 7% he would have earned $420 in interest. Also if total investment was switched from 6000 to 600 the 46 in interest would work.

.07x+.08(6000-x)=460

.07x-.08x+480=460

-.01x+480=460

-.01x=-20

x=$2000

which is easy enough to check

2000(.07)+4000(.08)=$460