At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

WILL GIVE BRAINLIEST

Use the following information to find the test statistic of the sample used to test the claim that daily rainfall amounts in the northeastern United States are less than 0.13 inches.
n = 45, x = 0.10 in., s = 0.26 in.
t = –8.263

t = –0.774

t = –2.580

t = –0.395

Sagot :

Using the t-distribution, the test statistic is given as follows: t = -0.774.

What is the test statistic of a t-distribution test hypothesis?

The test statistic is given by:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

The parameters are:

  • [tex]\overline{x}[/tex] is the sample mean.
  • [tex]\mu[/tex] is the tested value.
  • s is the standard deviation of the sample.
  • n is the sample size.

The values of the parameters for this problem are:

[tex]\overline{x} = 0.1, \mu = 0.13, s = 0.26, n = 45[/tex]

Hence the test statistic is:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{0.1 - 0.13}{\frac{0.26}{\sqrt{45}}}[/tex]

t = -0.774.

More can be learned about the t-distribution at https://brainly.com/question/13873630

#SPJ1