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A 50 kg boy jumps off the front of a 1.5 kg skateboard moving forward. Find the skateboard's velocity
immediately after the boy jumps, assuming that the skateboard's initial velocity is 3.5 m/s and the boy's
velocity when jumping off the front is 5 m/s?

Sagot :

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Answer:

The speed is 1.35 m/s

Explanation:

(m1+m2) vi= m1+m2v2

(50+1.5) (3.5)=50 (5+v2) +1.5 v2

180.25= 250+ 51.5 v2

180.25- 250+ 51.5 v2

-69.75= 51.5 v2

v2= -1.35 m

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