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Find the equation of the line passing
through the points (4, 2) and (6,10).
y = [ ? ]x + [ ]

Find The Equation Of The Line Passing Through The Points 4 2 And 610 Y X class=

Sagot :

y=4x-14

(Y2-Y1)/ (X2-X1) = slope
y= Mx+b. M= slope B= y-int.

(10-2) / (6-4) = 8/2
=4

(4,2) -> choose one point then plug in

2 = 4(4)+b
2 = 16+b
b= -14

y= 4x-14

The equation of the line passing through the points (4, 2) and (6,10) is y=4x-14.

We have given the points (4, 2) and (6,10).

What is the formula for slope?

(Y2-Y1)/ (X2-X1) = slope

What is the slope-intercept form?

y= Mx+b. M= slope B= y-int.

(10-2) / (6-4) = 8/2

Slope=4

(4,2)  choose one point then plug in

2 = 4(4)+b

2 = 16+b

b= -14

To learn more about the slope visit:

https://brainly.com/question/3493733

#SPJ2

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