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Sagot :
Answer:
Number of liters of 30% solution = x = 3.3 liters
Number of liters of 60% solution = y
= 6.67 liters
Step-by-step explanation:
Let us represent:
Number of liters of 30% solution = x
Number of liters of 60% solution = y
Determine the number of liters of a 30% saline solution and the number of liters of a 60% saline solution that are required to make 10 liters of a 50% saline solution.
30% × x + 60% × y = 10 × 50%
0.3x + 0.6y = 5...... Equation 1
x + y = 10...... Equation 2
x = 10 - y
We substitute 10 - y for x in Equation 1
Hence
0.3(10 - y) + 0.6y = 5
3 - 0.3y + 0.6y = 5
- 0.3y + 0.6y = 5 - 3
0.3y = 2
y = 2/0.3
y = 6.67 liters
Solving for x
x = 10 - y
x = 10 - 6.67
x = 3.33 liters
Hence:
Number of liters of 30% solution = x = 3.3 liters
Number of liters of 60% solution = y
= 6.67 liters
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