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if 315mL of 1.25 M iron(ii) sulfate is added to 405mL of.95 M ammonium phosphate, what is the limiting reactant


Sagot :

drpelezo

Answer:

FeSO₄ is the Limiting Reactant

Explanation:

3FeSO₄(aq) + 2(NH₄)₃PO₄ (aq) => 3(NH₄)₃PO₄(aq) + Fe₃(PO₄)(s)

315ml(1.25M)FeSO₄ + 405ml(0.95M)(NH₄)₃PO₄

=> 0.315L(1.25M)FeSO₄       +      0.405ml(0.95M)(NH₄)PO₄

=> 0.394mole FeSO₄           +      0.385mole (NH₄)PO₄

Divide by respective coefficient => the smaller value is the Limiting Reactant.

=> 0.394/3 = 0.131                      => 0.385/2 = 0.193

Smaller value is associated with FeSO₄

∴the limiting reactant is FeSO₄.

Summery:

1. convert reactant quantities to moles

2. divide reactants by respective coefficients of balanced equation

3. note smaller value after dividing by respective coefficient => Limiting Reactant.

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