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Sagot :
ax² + bx + c = 0
Let's write -9 where we see A:
-9x² + bx + c = 0
Let's write 0 where we see B:
-9x² + 0.x + c = 0
(Since B = 0, when it is multiplied by x, it becomes 0 again)
-9x² + c = 0
Let's write -2 where we see C:
-9x² + -2 = 0
Now we can move on to solving our equation:)
Let's put the known and the unknown on different sides:
(-2 goes to the opposite side positively)
-9x² = 2
(it goes as a division because it is in the case of multiplying -9 across)
x² = 2/-9
I could not find the rest of it, but I did not want to delete it for trying very hard. Sorry. It felt like we should take the square root, but I couldn't find it, maybe this can help you a little bit.
Please do not report:(
I hope I got it right, I'm trying to improve my English a little :)
Greetings from Turkey:)
#XBadeX
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