pashupatisingh03
Answered

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dy
If x2 - y2 = 1, then
dx
1
(a) yx-1
(C) xy-1
(b) -xy-
(d) - yx​

Sagot :

Answer:

xy-1

Explanation:

Given expression is :

[tex]x^2-y^2=1[/tex] ..(1)

We need to find the value of [tex]\dfrac{dy}{dx}[/tex].

Differentiating equation (1) wrt x.

[tex]\dfrac{d}{dx}(x^2-y^2)=1\\\\2x-2y\times \dfrac{dy}{dx}=0\\\\2y\times \dfrac{dy}{dx}=2x\\\\y\times \dfrac{dy}{dx}=x\\\\\dfrac{dy}{dx}=\dfrac{x}{y}[/tex]

or

[tex]\dfrac{dy}{dx}=xy^{-1}[/tex]

Hence, the correct option is (c) "xy-1".

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