emilybakerr
Answered

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write an exponential function y=ab^x for a graph that includes (2,4) and (3,16)

Sagot :

Answer:

Using the equation y = abx , substitute both of your given points into that equation.

 2 = ab2 and 4 = ab3   Solve each equation for a.

 2⁄b2    and 4⁄b3 = a    

Therefore, 2⁄b2 = 4⁄b3

Cross multiply: 2b3 = 4b2    

Divide both sides by b2

 2b = 4      

a = 2/4 = 1/2

b = 2

 y = 1 (2)x

2

Hope it helps

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Thank you

sqdancefan

9514 1404 393

Answer:

  y = (1/4)4^x

Step-by-step explanation:

In general, you can use a 2-point form to write the exponential function for points (x1, y1) and (x2, y2) as ...

  y = y1·(y2/y1)^((x -x1)/(x2 -x1))

Using the given points, this becomes ...

  y = 4·(16/4)^((x -2)/(3 -2)) = 4·4^(x-2)

We can eliminate the exponent arithmetic by making use of a couple of rules of exponents.

  y = 4·(4^x)(4^-2) = (4^-1)(4^x)

  y = (1/4)(4^x)

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