hdgoomba81
Answered

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Am I correct? (Perfect Square Form)

Am I Correct Perfect Square Form class=

Sagot :

MrRoyal

Answer:

[tex](x -3 )^2 = 10[/tex]

Step-by-step explanation:

Given

[tex]x^2 - 6x - 1 = 0[/tex]

Required: Express as a perfect square

[tex]x^2 - 6x - 1 = 0[/tex]

Add 10 to both sides

[tex]x^2 - 6x - 1 +10= 0+10[/tex]

[tex]x^2 - 6x +9= 10[/tex]

Expand

[tex]x^2 - 3x - 3x+9= 10[/tex]

Factorize:

[tex]x(x - 3) - 3(x - 3)= 10[/tex]

Factorize:

[tex](x -3 )(x - 3) = 10[/tex]

[tex](x -3 )^2 = 10[/tex]

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