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Sagot :
Answer:
464 grams.
Step-by-step explanation:
Amount of substance:
The amount of substance after t years is given by an equation in the following format:
[tex]A(t) = A(0)(1-r)^t[/tex]
In which A(0) is the initial amount and r is the decay rate, as a decimal.
Co-60 has a half life of 5.3 years.
This means that:
[tex]A(5.3) = 0.5A(0)[/tex]
We use this to find r. So
[tex]A(t) = A(0)(1-r)^t[/tex]
[tex]0.5A(0) = A(0)(1-r)^{5.3}[/tex]
[tex](1-r)^{5.3} = 0.5[/tex]
[tex]\sqrt[5.3]{(1-r)^{5.3}} = \sqrt[5.3]{0.5}[/tex]
[tex]1 - r = 0.5^{\frac{1}{5.3}}[/tex]
[tex]1 - r = 0.8774[/tex]
So
[tex]A(t) = A(0)(0.8774)^{t}[/tex]
If a pellet that has been in storage for 26.5 years contains 14.5g of Co-60, how much of this radioisotope was present when the pellet was put in storage?
We have that [tex]A(26.5) = 14.5[/tex], and use this to find A(0). So
[tex]A(t) = A(0)(0.8774)^{t}[/tex]
[tex]14.5 = A(0)(0.8774)^{26.5}[/tex]
[tex]A(0) = \frac{14.5}{(0.8774)^{26.5}}[/tex]
[tex]A(0) = 464[tex]
464 grams.
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