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a sports car has a mass of 1300kg.Starting from the rest the car generates a force of 4400 N.The frictional force opposing this motion is 280 N.What is the car’s acceleration

Sagot :

mac205

since the car moves, the force needed to move is greater than the frictional forces opposing it

a = 3.17m/s²

View image mac205
Eduard22sly

The acceleration of the car with a mass of 1300 kg which starts from rest generating a force of 4400 N and having a frictional force of 280 N is 3.17 m/s²

  • We'll begin by calculating the net force acting on the car. This can be obtained as follow:

Force (F) = 4400 N

Frictional force (Fբ) = 280 N

Net force (Fₙ) =?

Fₙ = F – Fբ

Fₙ = 4400 – 280

Fₙ = 4120 N

Thus, the net force acting on the car is 4120 N

  • Finally, we shall determine the acceleration of the car. This can be obtained as follow:

Mass (m) = 1300 Kg

Net force (F) = 4120 N

Acceleration (a) =?

Force = Mass × Acceleration

4120 = 1300 × a

Divide both side by 1300

[tex]a = \frac{4120}{1300}\\\\[/tex]

a = 3.17 m/s²

Therefore, the acceleration of the car is 3.17 m/s².

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