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Sagot :
since the car moves, the force needed to move is greater than the frictional forces opposing it
a = 3.17m/s²
The acceleration of the car with a mass of 1300 kg which starts from rest generating a force of 4400 N and having a frictional force of 280 N is 3.17 m/s²
- We'll begin by calculating the net force acting on the car. This can be obtained as follow:
Force (F) = 4400 N
Frictional force (Fբ) = 280 N
Net force (Fₙ) =?
Fₙ = F – Fբ
Fₙ = 4400 – 280
Fₙ = 4120 N
Thus, the net force acting on the car is 4120 N
- Finally, we shall determine the acceleration of the car. This can be obtained as follow:
Mass (m) = 1300 Kg
Net force (F) = 4120 N
Acceleration (a) =?
Force = Mass × Acceleration
4120 = 1300 × a
Divide both side by 1300
[tex]a = \frac{4120}{1300}\\\\[/tex]
a = 3.17 m/s²
Therefore, the acceleration of the car is 3.17 m/s².
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