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The present age of the father and his son is 32 years and 7 years respectively.
7
Find how many years ago the product of their age was 116.
product of the present age of their ​

Sagot :

stop000juyles

Answer:

ok so im so confused but like you know i tried and i got this:

X years ago, the father’s age and the son’s age would be (32 - x) and (7 - x) years old.

(32 - x)(7 - x) = 116

(x - 32)(x - 7) = 116

x^2 - 39x + 224 = 116

x^2 - 39x + 108 = 0

(x - 3)(x - 36) = 0

x = 3, 36

But (32 - x) > 0, so x does not equal to 36.

x = 3

3 years ago, the father would be 29 years old, and the son 4 years old.

i know it sounds crazy but i think its wrong lol

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