At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Answer: The system we need to use is:
A = T - 3
A = (2/3)*T
Solving this, we get:
In a bag, there are 9 tangerines and 6 apples.
Step-by-step explanation:
The question seems to be incomplete, by a quick online search i've found the complete question:
"A fruit stand sells bags of apples and tangerines. • Each bag has 3 fewer apples than tangerines. 2 • In each bag, the number of apples is 2/3 the number of tangerines..."
We know that:
A = number of apples in one bag
T = number of tangerines in one bag
We also know that:
"Each bag has 3 fewer apples than tangerines"
This can be written as:
A = T - 3
"In each bag, the number of apples is 2/3 the number of tangerines"
This can be written as:
A = (2/3)*T
Then we have a system of equations:
A = T - 3
A = (2/3)*T
This is the system of equations that can be used to solve for A and T, now let's solve this.
Because A means the same thing in both equations, then we can write:
A = T - 3 = A = (2/3)*T
Then:
T - 3 = (2/3)*T
We can solve this for T.
T - 3 = (2/3)*T
T - (2/3)*T = 3
(1 - 2/3)*T = 3
(1/3)*T = 3
T = 3/(1/3) = 3*3 = 9
This means that in each bag we have 9 tangerines in a bag.
Now we can use any of the two equations in the system to find the value of A.
I will use the first one:
A = T - 3
Now let's replace T by 9, then:
A = 9 - 3 = 6
A = 6
So there are 6 apples in a bag.
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.