Answered

Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

a metal of length 15.01m is heated until it's temperature rise by 60c.if it is new length is 15.05cm ,calculate it linear expansivity
​

Sagot :

MrRoyal

Answer:

[tex]\alpha = 4.44 * 10^{-5} ^\circ C^{-1}[/tex]

Explanation:

Given

[tex]L_1 = 15.01m[/tex]

[tex]L_2 = 15.05m[/tex]

[tex]\triangle T = 60^\circ C[/tex]

Required

Determine its linear expansivity

This is calculated as:

[tex]\alpha = \frac{L_2 - L_1}{\triangle T * L1}[/tex]

[tex]\alpha = \frac{15.05m - 15.01m}{60^\circ C* 15.01m}[/tex]

[tex]\alpha = \frac{0.04m}{60^\circ C * 15.01m}[/tex]

[tex]\alpha = \frac{0.04}{60^\circ C* 15.01}[/tex]

[tex]\alpha = \frac{0.04}{900.6^\circ C}[/tex]

[tex]\alpha = 0.00004441483^\circ C^{-1}[/tex]

[tex]\alpha = 4.441483 * 10^{-5} ^\circ C^{-1}[/tex]

[tex]\alpha = 4.44 * 10^{-5} ^\circ C^{-1}[/tex]

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.