demarionkiante
Answered

At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

The perimeter of a rectangle is 86. The length of the rectangle is one more than twice the width. Determine the length and width of the rectangle.

Sagot :

holdrenwyatt

There are two equation of the system

(1) The perimeter

    2(w + l) = p

    2(w + l) = 86

(2) The length and the width

     2w = l + 2

From the second equation

2w = l + 2

l + 2 = 2w

l = 2w - 2

Subtitute l with 2w - 2 in the first equation to find the width

2(w + l) = 86

2(w + 2w - 2) = 86

2(3w - 2) = 86

6w - 4 = 86

6w = 90

w = 15

Now, find the length by subtituting w with 15

l = 2w - 2

l = 2(15) - 2

l = 30 - 2

l = 28

The dimension of the rectangle

length = 28 cm

width = 15 cm

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.