Answer:
2.59g
Explanation:
Using Avagadro's law equation as follows:
V1/n1 = V2/n2
Where;
V1 = initial volume (litres)
V2 = final volume (litres)
n1 = first amount of gas in grams
n2 = second amount of gas in grams
According to the information provided in this question, v1 = 93.2L, v2 = 10.4L, n1 = 23.2 g, n2 = ?
Using V1/n1 = V2/n2
93.2/23.2 = 10.4/n2
Cross multiply
93.2 × n2 = 23.2 × 10.4
93.2n2 = 241.28
n2 = 241.28/93.2
n2 = 2.588
n2 = 2.59g
The mass of the gas is 2.59g that occupies a volume of 10.4 L under the same conditions.
V₁/n₁ = V₂/n₂
Where
V₁ = initial volume (litres)
V₂ = final volume (litres)
n₁ = first amount of gas in grams
n₂ = second amount of gas in grams
Given:
V₁ = 93.2L,
V₂ = 10.4L,
n₁ = 23.2 g,
To find:
n₂ = ?
On substituting the values:
93.2/23.2 = 10.4/n₂
93.2 * n₂ = 23.2 * 10.4
93.2* n₂ = 241.28
n₂ = 241.28/93.2
n₂ = 2.588
n₂ = 2.59g
Thus, the mass of the gas is 2.59g.
Find more information about Avogadro law here:
brainly.com/question/3491421
