Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Titanium(IV) chloride decomposes to form titanium and chlorine, like this:_____.
TiCl4(1)-→Ti(s) + 2 Cl 2(g)
At a certain temperature, a chemist finds that a reaction vessel containing a mixture of titanium(IV) chloride, titanium, and chlorine at equilibrium has the following composition:_____.
compound amount
TiCl4 4.18g
Ti 1.32g
Cl2 1.08g
Calculate the value of the equilibrium constant for this reaction. Round your answer to significant digits. Clears your work. Undoes your last action. Provides information about entering answers.

Sagot :

jufsanabriasa

Answer:

K = 8.6x10⁻⁶

Explanation:

a chemist finds that a 5.2L reaction vessel...

To solve this question we need first to find the equation of the equilibrium constant using the chemical eqiation:

TiCl₄(l) ⇄ Ti(s) + 2Cl₂(g)

The equilibrium constant expression is:

K = [Cl₂]²

Because equilibrium constant is defined as the ratio berween concentrationa of products over reactant powered to its reaction coefficient. But pure liquids as TiCl₄(l) and pure solids as Ti(s) are not taken into account

Now, we need to find the molar concentration of Cl₂, [Cl₂]:

Moles Cl₂ -Molar mass: 70.9g/mol-:

1.08g * (1mol / 70.9g) = 0.0152 moles / 5.2L =

2.93x10⁻³M = [Cl₂]

K = (2.93x10⁻³)²

K = 8.6x10⁻⁶

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.