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Find the perimeter of the following shape, rounded to the nearest tenth



Please Help Find The Perimeter Of The Following Shape Rounded To The Nearest Tenth class=

Sagot :

Answer:

19.1

Step-by-step explanation:

i took the testttttt

Perimeter is the sum of the length of the sides used to make the given figure. The perimeter of the given shape is 19.1 units.

What is the length of any line on the graph?

The distance or length of any line on the graph,

[tex]{\rm Distance} = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]

where,

d = distance or length of the line between points 1 and 2,

(x₁ , y₁) = coordinate of point 1,

(x₂ , y₂) = coordinate of point 2,

To find the perimeter of the given figure we need to calculate the length of each line segment on the given graph. Therefore, the length of the different sides of the given quadrilateral can be written as,

AB = √[(5-0)²+(-1-0)²] = √26 units

BC = √[(5-3)²+(-1+5)²] = √20 units

CD = √[(3+2)²+(-5+4)²] = √26 units

AD = √[(-4 - 0)²+(- 2 - 0)²] = √20 units

Perimeter = AB + BC + CD + AD

                 = √26 units + √20 units + √26 units + √20 units

                 = 19.1423 units ≈ 19.1 units

Hence, the perimeter of the given shape is 19.1 units.

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