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How many particles are in 9.58 x 1023 of potassium sulfate (K2SO4)? (5.77 x 1047 particles)

Sagot :

sebassandin

Answer:

[tex]5.77x10^{47}particles.[/tex]

Explanation:

Hello!

In this case, since we are given 9.58x10²³ moles of potassium sulfate, it is possible to compute the particles according to the Avogadro's number:

6.022x10²³

As shown below:

[tex]9.58x10^{23}mol*\frac{6.022x10^{23}}{1mol}\\\\5.77x10^{47}particles.[/tex]

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