Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

How many particles are in 9.58 x 1023 of potassium sulfate (K2SO4)? (5.77 x 1047 particles)

Sagot :

sebassandin

Answer:

[tex]5.77x10^{47}particles.[/tex]

Explanation:

Hello!

In this case, since we are given 9.58x10²³ moles of potassium sulfate, it is possible to compute the particles according to the Avogadro's number:

6.022x10²³

As shown below:

[tex]9.58x10^{23}mol*\frac{6.022x10^{23}}{1mol}\\\\5.77x10^{47}particles.[/tex]

Best regards!

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.