Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

The owner of a local nightclub has recently surveyed a random sample of 300 customers of the club. She would now like to determine whether or not the mean age of her customers is over 35. If so, she plans to alter the entertainment to appeal to an older crowd. If not, no entertainment changes will be made. Suppose she found that the sample mean was 35.5 years and population standard deviation was 5 years. What is the p-value associated with the test statistic

Sagot :

fichoh

Answer:

0.0416

Step-by-step explanation:

Given :

Sample size, n = 300

Sample mean, x = 35.5

Population mean, m = 35

Standard deviation, s = 5

The test statistic :

Zstatistic = (x - m) / s/sqrt(n)

Zstatistic = (35.5 - 35) / 5/sqrt(300)

Zstatistic = 0.5 / 0.2886751

Zstatistic = 1.732

Using the p value calculator from Zstatistic :

One tailed P value at 95% confidence interval is : 0.0416

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.