Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A custodian pulls a vacuum 13.5 m
with a 33.9 N force at a 55.0°
angle, against a 14.2 N friction
force. Find the total work done on
the vacuum.
(Unit = J)

Sagot :

BKRLA

Answer:

Horizontal component of pull = (cos 55 x 33.9) = 19.4N.

Net horizontal force = (19.4 - 14.2) = 5.2N.

Work = (fd) = (5.2 x 13.5) = 70.2 Joules.

Rounded to 1 decimal place throughout.

Explanation:

The total work done on the vacuum is 70.2 J.

What is work done?

Work done is equal to product of force applied and distance moved.

Work = Force x Distance

Given is a custodian pulls a vacuum 13.5 m with a 33.9 N force at a 55.0° angle, against a 14.2 N friction force.

Horizontal component of pull = (cos 55 x 33.9) = 19.4N.

Net horizontal force = (19.4 - 14.2) = 5.2N.

Work done by vacuum will be

Work =5.2 x 13.5

Work =70.2 J

Thus, the total work done on the vacuum is 70.2 J.

Learn more about work done

brainly.com/question/13662169

#SPJ5

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.