Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A light bulb has a resistance of 4 ohms and a current of 2 A. What is the voltage across the bulb?
volts

Sagot :

happiness20

Answer:

8 V

Explanation:

V= IR

V = 4×2

V= 8 V

The answer is the ohms × current

Voltage is an electrical difference of potential across the circuit. The voltage of the bulb is 8V with a current of 2 A and a resistance of 4 ohms.

What is ohms law?

Ohms law gives the relation between the current (I) in Amperes, voltage (V) in volts, and resistance (R) in ohms. The formula to calculate voltage is given as,

[tex]\rm V = I \times R[/tex]

Given,

Current (I) = 2 Ampere

Resistance (R) = 4 ohms

Substituting values in the equation to calculate voltage as:

[tex]\begin{aligned} \rm V &= \rm I \times R\\\\&= 2 \times 4 \\\\&= 8\end{aligned}[/tex]

Therefore, 8 V is the voltage developed across the bulb with 4-ohm resistance.

Learn more about voltage here:

https://brainly.com/question/15263092

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.