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Sagot :
On the table, x is in the left column, y is in the right.
Using the equation y = kx, we need to find k for that data
150 = k(1250)
150/1250 = k
0.12 = k
You can confirm that by doing the same with the second row, but I won’t put that here. It’s the same.
Dollars/kilowatt-hour is the label for the k of each equation (0.12, 0.15). We calculated dollars divided by (per) kWh.
Company P is less expensive than company M, because 0.12 < 0.15.
We need to buy 2,375 kWh of electricity from company P. The equation y = kx applies, where y is unknown, k = 0.12, and x = 2,375
y = (0.12)(2375)
y = $285
Let me know if you have any questions.
Using the equation y = kx, we need to find k for that data
150 = k(1250)
150/1250 = k
0.12 = k
You can confirm that by doing the same with the second row, but I won’t put that here. It’s the same.
Dollars/kilowatt-hour is the label for the k of each equation (0.12, 0.15). We calculated dollars divided by (per) kWh.
Company P is less expensive than company M, because 0.12 < 0.15.
We need to buy 2,375 kWh of electricity from company P. The equation y = kx applies, where y is unknown, k = 0.12, and x = 2,375
y = (0.12)(2375)
y = $285
Let me know if you have any questions.
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