Here , we are going to use Trigonometric ratios.
In given right angled ∆ ;
[tex]{:\implies \quad \sf \dfrac{x}{18}=\sin (60^{\circ}) \quad \bigg\{ \because \sin (\theta)=\dfrac{P}{H}\bigg\}}[/tex]
[tex]{:\implies \quad \sf x=\dfrac{18\sqrt{3}}{2} \quad \bigg\{\because \sin (60^{\circ})=\dfrac{\sqrt{3}}{2}\bigg\}}[/tex]
[tex]{:\implies \quad \bf \therefore \quad x=9\sqrt{3} \: units}[/tex]
Also;
[tex]{:\implies \quad \sf \dfrac{y}{18}=\cos (60^{\circ}) \quad \bigg\{ \because \cos (\theta)=\dfrac{B}{H}\bigg\}}[/tex]
[tex]{:\implies \quad \sf x=\dfrac{18}{2} \quad \bigg\{\because \cos (60^{\circ})=\dfrac{1}{2}\bigg\}}[/tex]
[tex]{:\implies \quad \bf \therefore \quad y=9 \: units}[/tex]
Hence , The required values for x and y are 9√3 and 9 units
