gustavosando514
Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

The current in the wires of a circuit is 60.0 milliAmps. If the
voltage impressed across the ends of the circuit were
doubled and the resistance were tripled, then its new current
would be ___ milliAmps.

The Current In The Wires Of A Circuit Is 600 MilliAmps If The Voltage Impressed Across The Ends Of The Circuit Were Doubled And The Resistance Were Tripled Then class=

Sagot :

Answer:

I' = 40 mA

Explanation:

Given that,

The current in the wires of a circuit is 60.0 mA.

If the  voltage impressed across the ends of the circuit were  doubled and the resistance were tripled such that,

V' = 2V and R'=3R

The relation between current, voltage and resistance is given by :

V = IR

Let I' be the new current. So,

V'=I'R'

⇒ [tex]I'=\dfrac{V'}{R'}\\\\I'=\dfrac{2V}{3R}\\\\I'=\dfrac{2}{3}\times \dfrac{V}{R}\\\\I'=\dfrac{2}{3}\times I\\\\I'=\dfrac{2}{3}\times 60\\\\I'=40\ mA[/tex]

So, the new current would be 40 mA.

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.