gustavosando514
Answered

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The current in the wires of a circuit is 60.0 milliAmps. If the
voltage impressed across the ends of the circuit were
doubled and the resistance were tripled, then its new current
would be ___ milliAmps.

The Current In The Wires Of A Circuit Is 600 MilliAmps If The Voltage Impressed Across The Ends Of The Circuit Were Doubled And The Resistance Were Tripled Then class=

Sagot :

Answer:

I' = 40 mA

Explanation:

Given that,

The current in the wires of a circuit is 60.0 mA.

If the  voltage impressed across the ends of the circuit were  doubled and the resistance were tripled such that,

V' = 2V and R'=3R

The relation between current, voltage and resistance is given by :

V = IR

Let I' be the new current. So,

V'=I'R'

⇒ [tex]I'=\dfrac{V'}{R'}\\\\I'=\dfrac{2V}{3R}\\\\I'=\dfrac{2}{3}\times \dfrac{V}{R}\\\\I'=\dfrac{2}{3}\times I\\\\I'=\dfrac{2}{3}\times 60\\\\I'=40\ mA[/tex]

So, the new current would be 40 mA.

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