Answered

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marbles numbered from 1 to 12 are put in a bag. if marbles are not put back into the bag after being drawn, what is the probability of drawing two prime numbers in a row?

Sagot :

MrRoyal

Answer:

[tex]Probability = \frac{1}{11}[/tex]

Step-by-step explanation:

Given

Marbles = 12

Selection without replacement

Required

Determine the probability of selecting 2 primes

Between 1 and 12, the prime digits is 4, and they are: 3, 5, 7 and 11

So, when the first marble is picked, the probability that it will be prime is:

[tex]P(First) = \frac{4}{12}[/tex]

Now there are 3 primes left and 11 marbles in total. So, the probability of selecting another prime is:

[tex]P(Second) = \frac{3}{11}[/tex]

The required probability is:

[tex]Probability = P(First) * P(Second)[/tex]

[tex]Probability = \frac{4}{12} * \frac{3}{11}[/tex]

[tex]Probability = \frac{1}{11}[/tex]

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