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Sagot :
We can find the side length of square 3 by dividing by 4, which is 9.
Then, we find the side length of square 2 by dividing it by 4, which is 12.
To find the AREA of square 1, we do a^2+b^2=c^2. This is basically adding up area of square 1 and square 2 to get square 3.
a^2+b^2=c^2
9^2+12^2=c^2
81+144=225
So the area is 225 units.
Then, we find the side length of square 2 by dividing it by 4, which is 12.
To find the AREA of square 1, we do a^2+b^2=c^2. This is basically adding up area of square 1 and square 2 to get square 3.
a^2+b^2=c^2
9^2+12^2=c^2
81+144=225
So the area is 225 units.
Answer:
225
Step-by-step explanation:
length of side in square 3 = 36/4
=9
length of side in square 2 = 48/ 4
= 12
using pythagorus theorem you can find side of square 1
take the triangle between 3 and 2
9^2 + 12^2 = length of side 1^2
81 + 144 = l^2
225 = l^2
l = 15
therefore length of side 1 is 15
area of square 1 = 15^15
area = 225 square units
hope this helped
ask if you didn't understand something or you think i am wrong:)
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