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Find the equation of the line through the points (-8,3) and (-4,5).

Sagot :

MrRoyal

Answer:

[tex]2y - x = 14[/tex]

Step-by-step explanation:

Given

[tex](x_1,y_1) = (-8,3)[/tex]

[tex](x_2,y_2) = (-4,5)[/tex]

Required

The line equation

First, calculate the slope (m)

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

[tex]m = \frac{5 - 3}{-4 - (-8)}[/tex]

[tex]m = \frac{2}{4}[/tex]

[tex]m = \frac{1}{2}[/tex]

The equation is then calculated as:

[tex]y = m(x - x_1) + y_1[/tex]

[tex]y = \frac{1}{2}(x - (-8)) +3[/tex]

[tex]y = \frac{1}{2}(x +8) +3[/tex]

Open bracket

[tex]y = \frac{1}{2}x +4 +3[/tex]

[tex]y = \frac{1}{2}x +7[/tex]

Multiply through by 2

[tex]2y = x + 14[/tex]

[tex]2y - x = 14[/tex]

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