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The points (-3, -3) and (5, r) lie on a line with slope 3/2
Find the missing coordinate r.

Sagot :

xero099

Answer:

The missing coordinate [tex]r[/tex] is 9.

Step-by-step explanation:

Given the points [tex]P(x,y) = (-3,-3)[/tex] and [tex]Q(x,y) = (5,r)[/tex], the slope of a line passing the two points ([tex]m_{PQ}[/tex]) is determined by equation of secant line:

[tex]m_{PQ} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}}[/tex] (1)

[tex]m_{PQ} = \frac{r-(-3)}{5-(-3)}[/tex]

If we know that [tex]m_{PQ} = \frac{3}{2}[/tex], then the value of [tex]r[/tex] is:

[tex]\frac{3}{2} = \frac{r+3}{8}[/tex]

[tex]12 = r + 3[/tex]

[tex]r = 9[/tex]

The missing coordinate [tex]r[/tex] is 9.

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