Answered

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She must throw two fair dice.
She must get a 6 on each dice to start the game.
Work out the probability that she will not start the game on her first throw.

Sagot :

so the probability that she will get a six on die 1 is 1/6 and the probability she will get a 6 on die 2 is also 1/6 add these together and the probability she will get two 6’s is 2/12 meaning that the probability she won’t is 12/12 - 2/12 = 10/12
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