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What is the equation of the line that passes through the point (-4, -7) and has a
slope of 2/3 ?

Sagot :

Answer:

Step-by-step explanation:

(-4 , -7) ; slope = (2/3)

y -y1 =m(x-x1)

[tex]y -[-7]=\frac{2}{3}(x-[4])\\\\y+7 = \frac{2}{3}(x+4)\\\\y+7=\frac{2}{3}x+4*\frac{2}{3}\\\\y +7 = \frac{2}{3}x+\frac{8}{3}\\\\y=\frac{2}{3}x+\frac{8}{3}-7\\\\y=\frac{2}{3}x+\frac{8}{3}-\frac{7*3}{1*3}\\\\y=\frac{2}{3}x+\frac{8}{3}-\frac{21}{3}\\\\y=\frac{2}{3}x-\frac{13}{3}[/tex]