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3(2x+d)+c(x+5)=10x+17 find c and d

Sagot :

Answer:

c = 4, d = - 1

Step-by-step explanation:

Expand and simplify left side, then compare coefficients of like terms on the right side, that is

3(2x + d) + c(x + 5) ← distribute parenthesis

6x + 3d + cx + 5c

= x(6 + c) + 3d + 5c

Compare terms with those on the right side

coefficients of x- terms

6 + c = 10 ( subtract 6 from both sides )

c = 4

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constant terms

3d + 5c = 17, that is

3d + 5(4) = 17

3d + 20 = 17 ( subtract 20 from both sides )

3d = - 3 ( divide both sides by 3 )

d = - 1

abidemiokin

The value of c and d if 3(2x+d)+c(x+5)=10x+17  is 4 and -1 respectively

Given the equation:

3(2x+d)+c(x+5)=10x+17

Expand the bracket

6x + 3d + cx + 5c = 10x + 17

Collect the like terms

6x+cx + 3d + 5c = 10x + 17

x(6+c) + 3d + 5c = 10x + 17

Compare the coefficients of x on both sides

x(6+c) = 10x

6+c = 10

c = 10 - 6

c = 4

Similarly:

3d + 5c = 17

3d + 5(4) = 17

3d + 20 = 17

3d = 17 - 20

3d = -3

d =-3/3

d = -1

Hence the value of c and d if 3(2x+d)+c(x+5)=10x+17  is 4 and -1 respectively

Learn more here: https://brainly.com/question/945593

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