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A ball is thrown from an initial height of 6 feet with an initial upward velocity of 17 ft/s. The ball's height h (in feet) after t seconds is given by the following.


h=6+17t-16t^2


Find all values of t for which the ball's height is 10 feet.


Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)
t=___seconds


Sagot :

Answer:

6 + 29t - 16t^2 = 18

16t^2 - 29t + 12 = 0

t = (29 +- √(29^2 - 4*12*16))/32

t = (29 +- √73)/32

t  = 0.639249882958827, 1.1732501170411

Step-by-step explanation: